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other contributions, I developed a new test for semiconductor chips as a result of such an incentive. In Straight from the CEO (1998), G. William Dauphinais and Colin Price quantified the degree of creativity required for developing innovative ideas. From a pool of 3000 ideas, about 300 are processed for their innovative potential. About 125 are converted to full-fledged projects, and about 2 products are eventually launched. It becomes obvious, then, that to launch an innovative product, R&D engineers alone cannot do it. On the contrary, launching an innovative product requires the creativity of the entire workforce. J. Morcott Southwood at Dana Corporation observed that the ratio of implemented to suggested ideas improved continually. As the leadership provides focus and structure for creativity, employee ideas become more relevant to the corporate needs instead of just being personally creative. However, employees intellectual freedom must be nurtured and nourished to extract great ideas from them. Any one of us has a potential to be a great innovator, given the right environment. Companies that facilitate employees creativity have realized tremendous financial benefits. Actually, most of the growth of businesses, when it occurs, happens through innovation. Figure 10-7 captures the innovative process in an organization. Accordingly, an organization must establish a system for managing the innovation process effectively and measuring its effectiveness for continually improving the economic value of innovation.

Figure 12-3

Suppose that you want to display the names of CDs and the amount in stock for CDs that are performed by blues artists. The DISC_INVENTORY table contains the names of the CDs and the amount in stock for each one, the DISC_ARTISTS table contains the names of the artists, and the DISC_TYPES table contains the names of the artist types. The DISC_ INVENTORY and DISC_ARTISTS tables are related through the ARTIST_ID column in each table. The DISC_ARTISTS and DISC_TYPES tables are related through the DISC_TYPE_ID column in each table. In order to return the information you need, you must query all three tables, as shown in the following SELECT statement:

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Within a user-defined array, the individual components (members) of a subscripted variable can be accessed as array name (subscript).member name These components can be used in the same manner as ordinary variables. Thus, they can appear within expressions, and they can be assigned values (see Secs. 2.5 and 2.10).

SELECT DISC_NAME, STOCK_AMOUNT FROM DISC_INVENTORY WHERE ARTIST_ID IN ( SELECT ARTIST_ID FROM DISC_ARTISTS WHERE DISC_TYPE_ID IN ( SELECT DISC_TYPE_ID FROM DISC_TYPES WHERE DISC_TYPE_NAME = 'Blues' ) );

In this statement, the primary SELECT statement queries the DISC_INVENTORY table. The statement includes a subquery in an IN predicate in the WHERE clause. The subquery is a SELECT statement that queries the DISC_ARTISTS table. The subquery, like the primary SELECT statement, includes an IN predicate in the WHERE clause, and this predicate also includes a subquery. As is the case with the outer subquery, the inner subquery includes a SELECT statement. However, in this case, the statement is querying the DISC_TYPES table.

FIGURE 10-7.

To better understand how the entire SELECT statement works, let s first look at the inner subquery. If you were to execute this statement alone, it would return a value of 11, which is the DISC_TYPE_ID value for the DISC_TYPE_NAME value of Blues. The outer subquery uses this value in the IN predicate to return those rows with a DISC_TYPE_ID value of 11. In this case, the only row returned is the B.B. King row, which has an ARTIST_ID value of 103. The ARTIST_ID value is then used in the IN predicate of the primary SELECT statement to return only those rows that contain an ARTIST_ID value of 103. If you execute the entire SELECT statement, you ll receive the following query results:

DISC_NAME -----------------Blues on the Bayou Deuces Wild STOCK_AMOUNT -----------19 17

As you can see, only two rows are returned. Notice that the results don t include any information from the DISC_ARTISTS table or the DISC_TYPES table, although these two tables are integral to arriving at these results. If you had wanted, you could have nested additional subqueries in your statement. Each one would have been processed in the same manner as the subqueries shown in the previous example.

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